Systems of Simultaneous Linear Equations: Numerical Problems
What Are Systems of Simultaneous Linear Equations?
A system of simultaneous linear equations is a collection of two or more linear equations involving multiple variables, where the equations are solved together because the variables are interdependent.
Each equation represents a relationship between variables, and the solution is a set of values that satisfies all equations at the same time.
Its uses in Economics
In economics, many variables are interrelated. For instance:
- Consumption depends on income,
- Income depends on investment,
- Investment may depend on interest rates.
These relationships are modeled using simultaneous equations to understand how changes in one variable affect others within an economic system.
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NP1: Solve the given system of simultaneous equations:
Solution:
From (2):
Substitute into (1):
Now plug y=2y = 2y=2 into (2):
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NP2: Solve the given system of simultaneous equations:
Solution:
Multiply (1) by 2:
Subtract (2) from (3):
Now plug into (1):
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Application in Economics:
NP1: A commodity is produced by 3 units of labour and 2 units of capital. The total cost comes to 62. If the commodity is produced by using 4 units of labour and 1 unit of capital, the cost comes to 56. What is the cost per unit of labour and capital?
Solution:
Given:
Where:
- L is the cost per unit of labour
- K is the cost per unit of capital
Solving by elimination method:
To do that, multiply Equation 2 by 2:
Subtract (1) from (3):
Substitute in (2)
Cost per unit of Labour (L) =
₹10 and cost per unit of Capital (K) = ₹16
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NP2: A product is made using 5 units of labour and 2 units of capital, costing ₹74. Another product uses 3 units of labour and 4 units of capital, costing ₹78. Find the cost per unit of labour and capital.
Solution:
Given:
Where:
L is the cost per unit of labour
K is the cost per unit of capital
Solving by elimination method:
To do that, multiply Equation (1) by 2:
Subtract (2) from (3):
Substitute in (1)
⇒
Cost per unit of Labour (L) =
₹10 and cost per unit of Capital (K) = ₹12
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NP3: A consumer buys two goods: Good A and Good B. When they buy 4 units of A and 6 units of B, they spend ₹72. When they buy 6 units of A and 3 units of B, they spend ₹75. Find the price per unit of Good A and Good B.
Solution:
Given:
Let:
A = price per unit of Good A
B = price per unit of Good B
Solving by elimination method:
To do that, multiply Equation (2) by 2:
Subtract (2) from (3):
Substitute in (1)
⇒
⇒
⇒
⇒
The price per
unit of Good A = 9.75 and Good B = 5.5
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NP4: A producer uses 2 tonnes of steel and 3 tonnes of copper to make a product costing ₹132. Another variation uses 5 tonnes of steel and 1 tonne of copper, costing ₹140. Find price per tonne of steel and copper.
Solution:
Given:
Let:
S = price of steel
C = price of copper
Solving by elimination method:
To do that, multiply Equation (2) by 3:
Subtract (1) from (3):
Substitute in (1)
⇒
⇒
⇒
The price per tonne of steel
and copper are:
Steel = ₹22.15/tonne
Copper = ₹29.25/tonne
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